Chem – College: Dating Anywhere between Acidic and you can Feet Equilirium Constants (Ka and you may Kb)

Written by on October 22, 2022

Chem – College: Dating Anywhere between Acidic and you can Feet Equilirium Constants (Ka and you may Kb)

When you are given multiple Ka or Kb values (like Ka step 1 , Ka dos , Ka step three ), you can also combine them together into an overall Ka or Kb by multiplying them together. The equations below display what I mean.

If Mg(OH) 2 has a Kb 1 of 0.3 and a Kb 2 of 4.5 planetromeo bezplatná aplikace * 10 -3 what is the over all Kb value?

In the event that Become(OH)

If H 3 PO 4 has a Ka 1 of 2.8 * 10 -3 and a Ka 2 of 7.1 * 10 -6 . 3 if the overall Ka is 7.75 * 10 -17 ?

Answer: ( 2.8 * 10 -3 ) * ( 7.1 * 10 -6 ) * Ka 3 = 7.75 * 10 -17

If Al(OH) 3 has a Kb 1 of 0.04 and a Kb 2 of 5.1 * 10 -4 what is the over all Kb value?

If H 2 SO 4 has a Ka 1 of 15 and a Ka 2 of 2.0 * 10 -2 . Then what is the over all Ka value?

If H 3 PO 3 has Ka 2 of 4.7 * 10 -5 and a Ka 3 of 2.3 * 10 -8 . 1 if the overall Ka is 5.5 * 10 -16 ?

Answer: Ka1 * (4.7 * 10 -5 ) * (2.3 * 10 -8 ) = 5.5 * 10 -16 — Ka1 = 5.09 * 10 -4

2 has a Kb 1 of 3.6 * 10 -4 and an overall Kb of 8.2 * 10 -12 what would be the Kb 2 ?

Answer: (3.6 * 10 -4 ) * Kb 2 = 8.2 * 10 -12 — Kb 2 = 2.24 * 10 -8

As it happens you to definitely Ka and you may Kb is actually pertaining to one another from inside the an algorithm. This formula allows you to move off Ka to help you Kb and you may vise versa. The fresh new algorithm try found below .

The wonderful thing about it formula will it be and allows you so you’re able to predict whether or not something is actually an acid otherwise a base . How you can figure if something are an acidic otherwise legs by just their Ka otherwise Kb well worth is always to evaluate they into the harmony lingering to have drinking water like in the new equation less than.

In the event the Ka transforms going to end up being a more impressive amount than simply brand new Kb then chemical could well be an acid.

If for example the Kb converts planning to end up being a bigger amount than just the brand new Ka then the toxins could be a base.

Allow the Kb and you may give whether the toxins is an acid otherwise foot in the event it enjoys a good Ka out of 2.cuatro * ten -6 .

Answer: Acid (Ka are bigger than Kb), Kb = 10 -fourteen / 2.cuatro * ten -six = cuatro.17 * ten -9

Allow the Ka and you may share with perhaps the agents is actually an acid or ft whether it possess a good Kb out of step 3.5 * 10 -cuatro .

Answer: Foot (Kb is actually bigger than Ka), Ka = ten -fourteen / 3.5 * ten -4 = dos.86 * ten -eleven

Give the Kb and you will tell perhaps the agents are an acid otherwise base when it provides a great Ka from 4.step 3 * 10 -9 .

Answer: Feet (Kb try larger than Ka), Kb = 10 -fourteen / cuatro.3 * ten -nine = 2.thirty two * ten -6

Provide the Ka and tell if the agents try an acid or legs when it enjoys a Kb of 8.nine * ten -eleven .

Answer: Acidic (Ka are larger than Kb), Ka = 10 -14 / 8.nine * 10 -11 = step one.12 * ten -4

Provide the Kb and give if the agents is actually an acidic or foot in the event it has an effective Ka from eight.dos * ten -nine .

Answer: Feet (Kb is larger than Ka), Kb = ten -14 / 7.dos * 10 -9 = 1.38 * 10 -6

Allow the Ka and share with whether the chemical was an acidic otherwise ft whether or not it provides an effective Kb out of cuatro.dos * 10 -twelve .

Answer: Acid (Ka is actually larger than Kb), Ka = ten -fourteen / cuatro.dos * ten -eleven = dos.38 * ten -4

Provide the Kb and you may tell whether the chemicals was an acidic otherwise foot when it keeps a great Ka off step three.cuatro * ten -step three .

Then what might function as the Ka

Answer: Acidic (Ka is larger than Kb), Kb = 10 -fourteen / 3.4 * ten -3 = 2.94 * ten -several

Allow the Ka and you may give whether the agents try an acid otherwise ft in the event it has an excellent Kb of five.6 * 10 -7 .

Answer: Legs (Kb is actually bigger than Ka), Ka = ten -14 / 5.six * ten -seven = step one.78 * 10 -8


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